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  • Exam Code: 2V0-11.25
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NEW QUESTION: 1
You need an algorithm that must:
Iterate through an array of primitive integers
Print the value of each array element in index order
If the value of the element is equal to 10, print the value of the element, and then terminate the iteration
Which method correctly implements the algorithm?
A. public static void foo(int[] list) {
for(int i=0; i < list.length; i++) {
System.out.println(i);
if (i==10) continue;
}
B. public static void foo(int[] list) {
for(int i:list) {
System.out.println(i);
if (i==10) break;
}
C. public static void foo(int[] list) {
for(int i=0; i < list.length; i++) {
System.out.println(i);
if (i==10) break;
}
D. public static void foo(int[] list) {
while(list.length > 0) {
System.out.println(i);
if (i==10) break;
}
E. public static void foo(int[] list) {
for each(int i in list) {
System.out.println(i);
if (i==10) terminate;
}
Answer: B

NEW QUESTION: 2
HOTSPOT


Answer:
Explanation:


NEW QUESTION: 3
Your company's corporate telephony environment is a combination of Lync 2013 and traditional Private Branch Exchange (PBX). The sites are connected by a Multiprotocol Label Switching (MPLS) topology. There are 6,500 users enabled for Lync 2013 video conferencing. Only RTVideo is being used for video conferencing. On average, 12 percent of users are on a video conference at any one time. The company plans to add additional bandwidth for all sites.
The company is concerned about the quality of video conferences.
As part of a bandwidth upgrade process, you model real-time transport protocol (RTP) media call flows for video communications that use only RTVideo. You have determined the average number of video conferences and estimated the bandwidth required for the video portion.
You need to identify the additional bandwidth requirements when modeling real-time transport control protocol (RTCP).
Which bandwidth option should you choose?
A. 10 kilobits per second (kbps) per stream
B. 15 kilobits per second (kbps) per stream
C. 10 kilobits per second (kbps) total
D. 30 kilobits per second (kbps) total
Answer: A

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