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NEW QUESTION: 1
In a Steelhead Mobile deployment, what are Endpoint policies? (Select 2)
A. Templates that allow Steelhead Mobile clients to connect to Steelhead appliances
B. Configuration templates to configure computer-specific software settings on a Linux system
C. Configuration templates to configure groups of Steelhead Mobile clients that have the same configuration requirements
D. Configuration templates to configure groups of Steelhead Mobile clients that have the same datastore requirements
E. Steelhead Mobile client software default access policies used to connect to all Riverbed devices
Answer: C,D

NEW QUESTION: 2
You plan to create a new table that has the following requirements:
* Uses a GUID data type as the primary key.
* Uses a clustered index as the primary key.
* Minimizes fragmentation.
You need to recommend which option to include in the CREATE statement.
Which option should you include?
More than one answer choice may achieve the goal. Select the BEST answer.
A. IDENTITY
B. NEWSEQUENTIALID
C. @@IDENTITY
D. NEWID
Answer: B

NEW QUESTION: 3
展示を参照してください。

ip route 0.0.0.0 0.0.0.0 10.13.0.1 120コマンドを使用してルーターに静的デフォルトルートを構成する場合、ルーターはどのように応答しますか？
A. 2つのデフォルトルート間のトラフィックの負荷分散を開始します
B. ルーティングテーブルに一致する特定のエントリがないトラフィックをGigabitEthernetO / 1に送信し始めます
C. ルーティングテーブル内の既存のOSPFルートを、新しく構成された静的ルートですぐに置き換えます
D. 既存のOSPFデフォルトルートが削除されるまで、新しいスタティックルートを無視します
Answer: D

NEW QUESTION: 4
In the following SQL statement, what is the criteria used for partitioning?

A. yellow_pages
B. MAXVALUE
C. none
D. cell_id
E. pXX
Answer: D
Explanation:
Range Partitioning in Oracle
How does Oracle know how to decompose the single logical table into multiple smaller tables? The answer to this fundamental question is that the user or DBA establishes the criterion used by the database for partitioning. In the case of range partitioning, a partition key is specified. The partition key is based on one or more columns in the table that are associated with a value or range of values. Oracle uses the partition key to decide which partition (smaller table) to put each row in. For example, if the partition key is a date field, then Oracle will look at the date associated with the partition key, and insert that row into the smaller table that contains the range of dates associated with the given date.
For instance, given this table:
CREATE TABLE partn_table (in_date DATE, geom SDO_GEOMETRY)
PARTITION BY RANGE (in_date)
(PARTITION Q1_2004 VALUES LESS THAN ('01-APR-2004'),
PARTITION Q2_2004 VALUES LESS THAN ('01-JUL-2004'),
PARTITION Q3_2004 VALUES LESS THAN ('01-OCT-2004'),
PARTITION Q4_2004 VALUES LESS THAN ('01-JAN-2005')
);
The data is loaded as follows:

References:http://download.oracle.com/otndocs/products/spatial/pdf/spatial_wp10_bestpra c.pdf, page 3