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NEW QUESTION: 1
Sam is setting up federated login for his IBM Notes users. Which is a requirement for federated login?
A. The users' Notes IDs must be stored in an Identity Provider (IdP).
B. The users' Notes IDs must be stored in an ID Vault.
C. The users' Notes IDs must be stored in a roaming Personal Address Book.
D. The users' Notes IDs must be stored in a Smartcard.
Answer: B

NEW QUESTION: 2
All of the following are true under a system of floating (flexible) exchange rates except which one?
A. Balance of payments deficits and surpluses are automatically corrected.
B. Balance of payments adjustment occurs without any effect on the domestic economy.
C. The prices of imports and exports change as the supply and demand for the currency change.
D. There is no danger of long term undervaluation or overvaluation of the currency.
Answer: B

NEW QUESTION: 3
Access points ate deployed in an office building and users report that the real-time communications quality of experience is poor when users walk between the elevators The elevators are a heavy metallic obstacle, and AP
3 was installed to cover the elevator area, which AP t and AP 2 signal does not reach Communications are captured for a user walking from point A to point C. and it is observed that the user iPhone device suddenly scans all bands and then roams from AP I to AP 3 somewhere between points B and C WLAN is set to 5 GHz only. Open, default rate configuration. Which action improves the real-time application quality of experience in this area?
Refer to the exhibit.

A. Move AP 2 to point B
B. Enable 802 11r on the WLAN
C. Enable 802 11v on the WLAN
D. Enable 802 11k on the WLAN
Answer: B

NEW QUESTION: 4
Given the code fragment:

Which code fragment, when inserted at line 7, enables printing 100?
A. Function<Integer> funRef = e -> e + 10;
Integer result = funRef.apply(value);
B. ToIntFunction funRef = e -> e + 10;
int result = funRef.apply (value);
C. ToIntFunction<Integer> funRef = e -> e + 10;
int result = funRef.applyAsInt (value);
D. IntFunction funRef = e -> e + 10;
Integer result = funRef.apply (10);
Answer: A