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NEW QUESTION: 1
Refer to the exhibit. Catalyst R is the root bridge for both VLAN 1 and VLAN 2. What is the easiest way to load-share traffic across both trunks and maintain redundancy in case a link fails, without using any type of EtherChannel link-bundling?

A. Increase the root bridge priority (decreasing the numerical priority number) for VLAN 2 on Catalyst R so that R2 becomes the root port on Catalyst D for VLAN 2.
B. Decrease the path cost on R2 on Catalyst R for VLAN 2 so that port D1 will be blocked for VLAN 2 and port D2 will remain blocked for VLAN 1.
C. Decrease the port priority on R2 for VLAN 2 on Catalyst R so that port D1 will be blocked for VLAN 2 and port D2 will remain blocked for VLAN 1.
D. Increase the root bridge priority (increasing the numerical priority number) for VLAN 2 on Catalyst D so that port D2 becomes the root port on Catalyst D for VLAN 2.
Answer: C
Explanation:
First we should understand what will happen if nothing is configured (use default values). Because R is the root bridge so all of its ports will forward. D will need to block one of its ports to avoid a bridging loop between the two switches. But how does D select its blocked port? Well, the answer is based on the BPDUs it receives from R.
A BPDU is superior than another if it has:
1.A lower Root Bridge ID
2.A lower path cost to the Root
3.A lower Sending Bridge ID
4.A lower Sending Port ID
These four parameters are examined in order. In this case, all the BPDUs sent by R have the same Root Bridge ID, same path cost to the Root and same Sending Bridge ID. The only parameter left to select the best one is the Sending Port ID (Port ID = port priority + port index). If
using default values, the default port priority's value is 32 or 128 (128 is much more popular today), so D will compare port index values, which are unique to each port on the switch, and because port R2 is inferior to port R1 (the port's number of R2 is higher than that of R1, for example port Fa0/2 is inferior to port Fa0/1), D will select the port connected with port R1 as its root port and block the other port.
The problem here is port D2 is blocked for both VLAN 1 & 2 and that means we can't use the underneath link for load-sharing. The underneath link is just used in the case the above link fails.
Now as you can guess, the easiest way to load-share traffic across both trunks is decreasing the port priority on R2 for VLAN 2 on Catalyst R so that port D1 will be blocked for VLAN 2. Notice that "decreasing" here means make that port ID superior to the other port.

NEW QUESTION: 2
Ferris Plastics、Inc.は中規模企業で、ユーザーPCから企業サーバーへのLAN接続を提供するエンタープライズネットワーク（アクセス、ディストリビューション、コアスイッチ）を備えています。 分散スイッチは、HSRPを使用して高可用性ソリューションを提供するように設定されています。
* DSW1 - VLAN 101 VLAN 102およびVLAN 105用のプライマリデバイス
* DSW2 - VLAN 103およびVLAN 104のプライマリデバイス
*プライマリデバイスのGigabitEthemet1 / 0/1に障害が発生すると、バックアップデバイスのGigabitEthernet1 / 0/1も障害が発生していない限り、プライマリデバイスのステータスがプライマリデバイスとして解放されます。
トラブルシューティングではいくつかの問題が特定されています。 現在、すべてのインターフェースが稼動しています。 実行コンフィギュレーションとshowコマンドを使用して、次の質問を調査して対応するよう求められました。



日常のメンテナンス中に、DSW1のGigabitEthernet1 / 0/1インターフェイスをシャットダウンする必要がありました。 他のすべてのインターフェースは稼動していました。 この間、DSW1はVLAN 102 HSRPグループのアクティブデバイスのままでした。 VLAN 102 HSRPグループのtrackコマンドのデクリメント値に問題があると判断しました。 グループを適切に機能させるためには何をする必要がありますか？
A. DWTのデクリメント値は、195より大きく205より小さくなければなりません。
B. DSW1の減分値は9より大きく15未満でなければなりません。
C. DWTのデクリメント値は、190より大きく200未満でなければなりません。
D. DSW1の減分値は11より大きく19より小さくなければなりません。
E. DSW1の減分値は5より大きく15未満でなければなりません。
Answer: D
Explanation:
Explanation
The question clearly stated that there was an issue with the decrement value in VLAN 102 so we should check VLAN 102 on both DSW1 and DSW2 switches first. Click on the PC Console1 and PC Console2 to access these switches then use the "show running-config" command on both switches DSW1>enable DSW1#show running-config DSW2>enable DSW2#show running-config

As shown in the outputs, the DSW1's priority is 200 and is higher than that of DSW2 so DSW1 becomes active switch for the group. Notice that the interface Gig1/0/1 on DSW1 is being tracked so when this interface goes down, HSRP automatically reduces the router's priority by a congurable amount, in this case 5. Therefore the priority of DSW1 goes down from 200 to 195. But this value is still higher than that of DSW2 (190) so DSW1 remains the active switch for the group. To make DSW2 takes over this role, we have to configure DSW1's decrement value with a value equal or greater than 11 so that its result is smaller than that of DSW2 (200 - 11 < 190). Therefore C is the correct answer.

NEW QUESTION: 3

A. Option D
B. Option C
C. Option A
D. Option B
Answer: A

NEW QUESTION: 4








Answer:
Explanation:

Explanation
DataContractSerializer DataContract DataMember
Target 1: [DataContract(NameSpace=http://contoso.com/2012/06)]
Target 2: [DataMember(Order=10)]
Target 3: [DataMember]
Target 1: The DataContractAttribute.Namespace Property gets or sets the namespace for the data contract for the type. Use this property to specify a particular namespace if your type must return data that complies with a specific data contract.
Target2, target3: We put Order=10 on FirstName to ensure that LastName is ordered first.
Note:
The basic rules for data ordering include:
* If a data contract type is a part of an inheritance hierarchy, data members of its base types are always first in the order.
* Next in order are the current type's data members that do not have the Order property of the DataMemberAttribute attribute set, in alphabetical order.
* Next are any data members that have the Order property of the DataMemberAttribute attribute set. These are ordered by the value of the Order property first and then alphabetically if there is more than one member of a certain Order value. Order values may be skipped.
Reference: Data Member Order
https://msdn.microsoft.com/en-us/library/ms729813(v=vs.110).aspx
Reference: DataContractAttribute.Namespace Property
https://msdn.microsoft.com/en-us/library/system.runtime.serialization.datacontractattribute.namespace(v=vs.110