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NEW QUESTION: 1
The output of the show frame-relay pvc command shows "PVC STATUS = INACTIVE". What does this mean?
A. The PVC is not configured on the local switch.
B. The PVC is configured correctly on the local switch, but there is a problem on the remote end of the PVC
C. The PVC is configured correctly, is operating normally, and is no longer actively seeking the address of the remote router.
D. The PVC is configured correctly and is operating normally, but no data packets have been detected for more than five minutes.
E. The PVC is configured correctly, is operating normally, and is waiting for interesting traffic to trigger a call to the remote router.
Answer: B
Explanation:
The PVC STATUS displays the status of the PVC. The DCE device creates and sends the report to the DTE devices. There are 4 statuses:
ACTIVE: the PVC is operational and can transmit dataINACTIVE: the connection from the local router to the switch is working, but the connection to the remote router is not availableDELETED:
the PVC is not present and no LMI information is being received from the Frame Relay switch STATIC: the Local Management Interface (LMI) mechanism on the interface is disabled (by using the "no keepalive" command). This status is rarely seen.

NEW QUESTION: 2
How should you design the disk configurations for the mailbox servers at headquarters to achieve the best performance and fault tolerance?
A. Place the operating system and the transaction logs for all storage groups on a single mirrored pair of disk drives. Place each information store on its own RAID-5 volume.
B. Place the operating system on a mirrored pair of disk drives.
Place transaction logs for all storage groups on a single mirrored pair of disk drives.
Place the information stores on a single RAID-5 volume.
C. Place the operating system on a mirrored pair of disk drives.
Place transaction logs for each storage group on their own RAID-1 mirrored pair of disk drives.
Place the information stores on a single RAID-5 volume.
D. Place the operating system and the transaction logs for all storage groups on a single RAID-5 volume. Place each information store on its own RAID-5 volume.
Answer: C
Explanation:
Best performance and recovery process is Place each database mailbox store from each storage group in it own RAID (0+1) array Place the storage group transaction log in each own Raid 1 array, but if you can not afford this kind of configuration you can use Raid 5 array instead of Raid (0+1) arrays than mean Raid 10 In this case the best hardware solution is C Disk Performance Issues Unlike CPU performance issues, disk performance issues cannot be diagnosed with a single counter that indicates that you have a disk bottleneck.
Note:
A disk bottleneck can also be a result of memory issues, and cannot be solved by simply adding more spindles. Ensure when you size your Exchange 2000 disk configurations, to size for I/O capacity and not for disk space alone. Microsoft recommends RAID 0+1 because this configuration tends to result in more I/O capacity than RAID 5.
Disk Performance Issues: Approach One
The first approach to determining if you are encountering a disk bottleneck is to monitor the following counters for each of your physical drives.
* PhysicalDisk(drive:)\Disk Writes/sec
* PhysicalDisk(drive:)\Disk Reads/sec
Note:
Before troubleshooting disk performance problems, at the command prompt, run diskperf -y to activate logical, as well as physical, disk counters.
Look at each drive and compare to the total instance to isolate where the I/O is going. You can use the recommendations below to assist with the comparison and determine if you have a bottleneck.
* Raid-0: Reads/sec + Writes/sec < # Spindles x 100
* Raid-1: Reads/sec + 2 * Writes/sec < # Spindles x 100 (each write has to go to each mirror on the array)
* Raid-5: Reads/sec + 4 * Writes/sec < # Spindles x 100 (each write requires two reads and two writes) Note:
This assumes disk throughput is equal to 100 random I/O per spindle.
For more information about RAID, see the following "RAID Levels" section.
RAID Levels
Although there are many different implementations of RAID technologies, they all share twosimilar aspects. They all use multiple physical disks to distribute data, and they all store data according to a logic that is independent of the application for which they are storing data. This section discusses four primary implementations of RAID: RAID-0, RAID-1, RAID-0+1, and RAID-
5. Although there are many other RAID implementations, these four types serve as a representation of the overall scope of RAID solutions.
RAID-0
RAID-0 is a striped disk array; each disk is logically partitioned in such a way that a "stripe" runs across all the disks in the array to create a single logical partition. For example, if a file is saved to a RAID-0 array, and the application that is saving the file saves it to drive D, the RAID-0 array distributes the file across logical drive D (see Figure 13). In this example, it spans all six disks.

Figure 13 RAID-0 disk array
From a performance perspective, RAID-0 is the most efficient RAID technology because it can write to all six disks at once. When all disks store the application data, the most efficient use of the disks occurs.The drawback to RAID-0 is its lack of reliability. If the Exchange mailbox databases are stored across a RAID-0 array and a single disk fails, you must restore the mailbox databases to a functional disk array and restore the transaction log files. In addition, if you store the transaction log files on this array and you lose a disk, you can perform only a point-in-time restoration of the mailbox databases from the last backup.
RAID-1
RAID-1 is a mirrored disk array in which two disks are mirrored (see Figure 14).

Figure 14 RAID-1 disk arrays
RAID-1 is the most reliable of the three RAID disk arrays because all data is mirrored after it is written. You can use only half of the storage space on the disks. Although this may seem inefficient, RAID 1 is the preferred choice for data that requires the highest possible reliability.
RAID-0+1
A RAID-0+1 disk array allows for the highest performance while ensuring redundancy by combining elements of RAID-0 and RAID-1 (see Figure 15).

Figure 15 RAID-0+1 disk array
In a RAID-0+1 disk array, data is mirrored to both sets of disks (RAID-1), and then striped across the drives (RAID-0). Each physical disk is duplicated in the array. If you have a six-disk RAID-0+1 disk array, three disks are available for data storage.
RAID-5
RAID-5 is a striped disk array, similar to RAID-0 in that data is distributed across the array;however, RAID-5 also includes parity. This means that there is a mechanism that maintains the integrity of the data stored in the array, so that if one disk in the array fails, the data can be reconstructed from the remaining disks (see Figure 16). Thus, RAID-5 is a reliable storage solution.

Figure 16 RAID-5 disk array
However, to maintain parity among the disks, 1/n GB of disk space is sacrificed (where n equals the number of drives in the array). For example, if you have six 9-GB disks, you have 45 GB of usable storage space. To maintain parity, one write of data is translated into two writes and two reads in the RAID-5 array; thus, overall performance is degraded.
The advantage of a RAID-5 solution is that it is reliable and uses disk space more efficiently than RAID-1 (and 1+0).
For more information on comparing RAID solutions and RAID levels, as well as Storage Area Network (SAN) and Network Attached Storage (NAS) solutions, see the Storage Solutions for Microsoft Exchange 2000 Server white paper.
Disk Performance Problems: Approach Two
The second approach to determining if you are encountering a disk bottleneck requires looking at the I/O requests waiting to be completed using the following disk queue counters.
PhysicalDisk(drive:)\Avg. Disk Queue
PhysicalDisk(drive:)\Current Disk Queue
The PhysicalDisk(drive:)\Avg. Disk Queue counter indicates the average queue length over the sampling interval. The PhysicalDisk(drive:)\Current Disk Queue counter reports the queue length value at the instant of sampling.
You are encountering a disk bottleneck if the average disk queue length is greater than the number of spindles on the array and the current disk queue length never equals zero. Short spikes in the queue length can drive up the queue length average artificially, so you must monitor the current disk queue length. If it drops to zero periodically, the queue is being cleared and you probably do not have a disk bottleneck.
Note:
When using this approach, correlate the queue length spikes with the MSExchangeIS\RPC Requests counter to confirm the effect on clients.
Disk Problems: Approach Three
For the third approach to determining if you are encountering a disk bottleneck, look at the I/O latency, which can give you an indication of the health of your disks:
PhysicalDisk(drive:)\Avg. Disk sec/Read
PhysicalDisk(drive:)\Avg. Disk sec/Write
A typical range is .005 to .020 seconds for random I/O. If write-back caching is enabled in the array controller, the PhysicalDisk(drive:)\Avg. Disk sec/Write counter should be less than .002 seconds.
If these counters are between .020 and .050 seconds, there is the possibility of a disk bottleneck.
If the counters are above .050 seconds, there is definitely a disk bottleneck.
Reference:
Troubleshooting Microsoft Exchange 2000 Server Performance
Exchange Core Documentation

NEW QUESTION: 3
To correctly read the Excel file shown below,

Which dialog box settings are appropriate? A)

B)

C)

D)

A. Exhibit A
B. Exhibit D
C. Exhibit B
D. Exhibit C
Answer: B

NEW QUESTION: 4
Examine this command for creating pluggable database PDB2 in container database CDB2 CREATE PLUGGABLE DATABASE pdb2 ADMIN USER pdb2_adrn IDENTIFIED BY 12 3pdb ROLES=(CONNECT) ; Select three options, any one of which is required for it to execute successfully.
A. Add the file_name_convert clause to the statement and set the pdb_file_name_convert parameter.
B. Add only the create_file_dest clause to the statement.
C. Set only the pdb_file_name_convert parameter.
D. Add the file_mame_comvert clause to the statement and enable Oracle Managed Files (OMF).
E. Enable only OMF.
F. Set the pdb_file_name_convert parameter and enable OMF.
Answer: A,D,F