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NEW QUESTION: 1
1 학년 단위 판매의 손익분기 점은 다음과 같습니다.
A. 36,495 대
B. 56.320 단위.
C. 46.080 단위.
D. 42.240 단위.
Answer: C
Explanation:
The breakeven point in unit sales equals total rests divided by the unit contribution margin UCM). Total fixed costs are US $1,520,640 $600,000 + 7,00 u + $352,800), and the UCM is US $33 [$4,950,000 contribution margin sales minus variable costs) -100,000 units sold]. Hence, the breakeven point in unit sales is 46,080 units US $1,520,640 + $33). Data regarding Year 1 operations for an enterprise that had no beginning or ending inventories are as follows:

The enterprise estimates that next year direct materials costs will increase by 10% and direct labor costs will increase by U' To U. unit to US $5.40 per unit. In addition, fixed selling expenses will increase by US $29,520_ All other costs will b. incurred at the same rates or amounts as the current year.

NEW QUESTION: 2
Which is MOST LIKELY to trigger premature closure of a programme?
A. The programme is no longer aligned with corporate strategy
B. There is a change of senior responsible owner
C. The last tranche has been completed as per the programme plan
D. The scope of one of the key projects has been changed
Answer: A

NEW QUESTION: 3
From a Customer Success perspective, which reason to monitor your customer's health is the most important?
A. Understanding your customer's health directly enables renewals.
B. It allows the customer to identify unused licenses so they can be addressed via a service improvement plan.
C. It provides the opportunity to address any changes in the customer's experience or actions around the solution.
D. It gives the customer valuable insight so they can automatically renew critical services on time.
Answer: A

NEW QUESTION: 4

A. 10.10.1.0/24 subnetted with mask 255.255.255.252
B. 10.10.0.0/16 subnetted with mask 255.255.255.252
C. 10.10.0.0/23 subnetted with mask 255.255.255.252
D. 10.10.1.0/25 subnetted with mask 255.255.255.252
E. 10.10.0.0/18 subnetted with mask 255.255.255.252
Answer: C
Explanation:
Explanation
We need 113 point-to-point links which equal to 113 sub-networks < 128 so we need to borrow 7
bits (because 2