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NEW QUESTION: 1
It is the third day of the 5 days CEH program and John is taking a session on Session Hijacking.
John resumes the session after lunch break and finds that one of the students "s missing. What is the ideal action that John should take under such circumstances?
A. Criticize the student about his/her behavior
B. Resume the session
C. Enquire about the problem from other students and wait
D. Wart until the student arrives
Answer: D

NEW QUESTION: 2
프로젝트의 대규모 JSON 데이터 세트가 개인 Amazon S3 버킷에 업로드되었습니다. Machine Learning Specialist는 Amazon SageMaker 노트북 인스턴스의 데이터에 안전하게 액세스하고 탐색하려고 합니다. 새로운 VPC가 생성되어 전문가에게 할당되었습니다. Amazon S3에 저장된 데이터 중 분석을 위해 전문가에게 액세스 권한을 부여하면서 유지 관리합니까?
A. SageMaker 제공 인터넷 액세스가 활성화된 상태에서 VPC 내에서 SageMaker 노트북 인스턴스 시작 S3 ACL을 사용하여 모든 그룹에 대한 읽기 권한을 여십시오.
B. SageMaker 제공 인터넷 액세스가 활성화 된 상태에서 VPC 내에서 SageMaker 노트북 인스턴스를 시작합니다. 버킷의 데이터에 액세스 하기 위해 S3 사전 서명된 URL 생성
C. VPC 내에서 SageMaker 노트북 인스턴스를 시작하고 노트북이 데이터에 액세스 할 수있는 S3 VPC 엔드 포인트 생성 Amazon S3에서 JSON 데이터 세트를 SageMaker 노트북 인스턴스의 ML 스토리지 볼륨으로 복사하고 로컬 데이터 세트에 대해 작업
D. VPC 내에서 SageMaker 노트북 인스턴스를 시작하고 노트북이 데이터에 액세스 할 수있는 S3 VPC 엔드 포인트 생성 VPC의 요청 만 S3 버킷에 액세스 할 수 있도록 사용자 지정 S3 버킷 정책을 정의하십시오.
Answer: C

NEW QUESTION: 3
TEXT
You have a database that contains the following tables.

You need to create a query that returns each complaint, the names of the employees handling the complaint, and the notes on each interaction. The Complaint field must be displayed first, followed by the employee's name and the notes. Complaints must be returned even if no interaction has occurred.
Construct the query using the following guidelines:
-Use two-part column names.
-Use one-part table names.
-Use the first letter of the table name as its alias.
-Do not Transact-SQL functions.
-Do not use implicit joins.
-Do not surround object names with square brackets.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within the code that has been provided as well as below it.

1 SELECT c.Complaint, e.Name, i.Notes
2 FROM Complaints c
3 JOIN
4 JOIN

Answer:
Explanation:
see explanation below.
Explanation:
1 SELECT c.Complaint, e.Name, i.Notes
2 FROM Complaints c
3 JOIN Interactions i ON c.ComplaintID = i.ComplaintID
4 JOIN Employees e ON i.EmployeeID = E.EmployeeID