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NEW QUESTION: 1

A. IPAM Administrator Role
B. IPAM DHCP Reservations Administrator Role
C. IPAM DHCP Administrator Role
D. DNS Record Administrator Role
Answer: C
Explanation:
Explanation
The IPAM DHCP administrator role completely manages DHCP servers.

Reference: What's New in IPAM

NEW QUESTION: 2
Click the Exhibit button.

Referring to the exhibit, what must be added to the existing configuration to ensure that per-prefix load balancing occurs?
A. family inet unicast
B. multihop
C. keep all
D. multipath
Answer: D

NEW QUESTION: 3
An x-bar control chart has been established with control limits of 3.245 and 3.257, n = 5. An
engineer collects the following sample and plots the average on the control chart: 3.257, 3,256, 3. 258, 3.259
A. the control limits are incorrect
B. the process is out of control
C. the process is not out of control
D. the engineer misused the control chart
Answer: D

NEW QUESTION: 4
A customer provides the information shown in the exhibit for the company's primary database environment. Solution requirements include meeting of exceeding the current I/O rate of the existing environment.
System name Name Max IOPS Avg IOPS Min IOPS Max BW (MBps) Avg BW (MBps) Min BW (MBps) Max Latency (ms) Avg Latency (ms) pldenxivg3 denoubivs_arch1 1101 20 0 274 5 0 3 2 pldenxivg3 denoubivs_arch2 3 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bin1 322 1 0 1 0 0 32 0 pldenxivg3 denoubivs_bin2 184 0 0 1 0 0 21 0 pldenxivg3 denoubivs_bkup1 2 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bkup2 25 0 0 2 0 0 0 0 pldenxivg3 denoubivs_bkup3 1 0 0 0 0 0 0 0 pldenxivg3 denoubivs_data1 997 39 0 128 3 0 28 2 pldenxivg3 denoubivs_data2 997 38 0 133 3 0 31 2 pldenxivg3 denoubivs_data3 1005 43 0 127 3 0 23 1 pldenxivg3 denoubivs_data4 2217 38 0 175 3 0 19 2 pldenxivg3 denoubivs_data5 1194 37 0 109 2 0 32 1 pldenxivg3 denoubivs_data6 1118 30 0 70 2 0 23 1 pldenxivg3 denoubivs_data7 1111 29 0 70 2 0 21 1 pldenxivg3 denoubivs_data8 2443 24 0 156 1 0 10 0 pldenxivg3 denoubivs_data9 1710 8 0 108 0 0 12 1 pldenxivg3 denoubivs_log1 2107 49 0 46 1 0 2 0 pldenxivg3 denoubivs_log2 2174 44 0 43 1 0 2 0 pldenxivg3 denoubivs_NJP_bin 8 0 0 0 0 0 0 0 pldenxivg3 denoubivs_NJP_data 1452 9 0 93 0 0 0 0 pldenxivg3 denoubivs_NJP_log 65 14 0 3 0 0 0 0 pldenxivg3 denoubivs_os1 16 0 0 0 0 0 0 0 pldenxivg3 denoubivs_os2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_pg1 12 0 0 1 0 0 0 0 pldenxivg3 denoubivs_pg2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_arch1 501 5 0 122 1 0 3 1 pldenxivg3 denoubivs_arch2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back1 1 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back3 2 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bin1 209 2 0 6 0 0 16 0 pldenxivg3 denoubivs_bin2 283 0 0 17 0 0 18 1 pldenxivg3 denoubivs_bin3 176 1 0 8 0 0 18 1 pldenxivg3 denoubivs_data1 3128 116 0 201 5 0 17 0 pldenxivg3 denoubivs_data2 1117 65 0 71 2 0 16 0 pldenxivg3 denoubivs_data3 1129 69 0 71 2 0 16 0 pldenxivg3 denoubivs_data4 1136 63 0 72 2 0 16 0 pldenxivg3 denoubivs_data5 1147 65 0 72 2 0 16 0 pldenxivg3 denoubivs_data6 3470 60 0 223 2 0 36 0 pldenxivg3 denoubivs_data7 2389 51 0 152 2 0 20 0 pldenxivg3 denoubivs_log1 204 12 0 13 0 0 2 0 pldenxivg3 denoubivs_log2 279 11 0 12 0 0 3 0 pldenxivg3 denoubivs_os1 21 0 0 0 0 0 0 0 pldenxivg3 denoubivs_os2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_pg1 2 0 0 0 0 0 0 0
Total= 35458 943 0 2580 44
Average= 788 21 0 57 1 0 10
0
What should the minimum I/O rate be for the new solution?
A. 788 I/Os per second
B. 21 I/Os per second
C. 943 I/Os per second
D. 35458 I/Os per second
Answer: B