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NEW QUESTION: 1


A. Option D
B. Option A
C. Option C
D. Option B
Answer: D
Explanation:
Explanation
Example:
// Signature specifies Task<TResult>
async Task<int> TaskOfTResult_MethodAsync()
{
int hours;
// . . .
// Return statement specifies an integer result.
return hours;
}
// Calls to TaskOfTResult_MethodAsync
Task<int> returnedTaskTResult = TaskOfTResult_MethodAsync();
int intResult = await returnedTaskTResult;
// or, in a single statement
int intResult = await TaskOfTResult_MethodAsync();
// Signature specifies Task
async Task Task_MethodAsync()
{
// . . .
// The method has no return statement.
}
// Calls to Task_MethodAsync
Task returnedTask = Task_MethodAsync();
await returnedTask;
// or, in a single statement
await Task_MethodAsync();
Reference: Asynchronous Programming with Async and Await (C# and Visual Basic)
https://msdn.microsoft.com/en-us/library/hh191443.aspx

NEW QUESTION: 2
What should an incident responder select in the Enforce management console to remediate multiple
incidents simultaneously?
A. Automated Response on the Incident Snapshot page
B. Smart response on the Incident page
C. Smart response on an Incident List report
D. Automated response on an Incident List report
Answer: A

NEW QUESTION: 3
새로운 프로젝트에는 다양한 부서의 특정 기술과 역량을 갖춘 리소스가 필요합니다. 대부분의 회사 직원은 이미 다른 프로젝트 관리자에게 배정되었으므로 사용 가능한 내부 인사를 식별하고 이에 동의하고 외부 전문가를 고용해야 합니다.
프로젝트 관리자는 먼저 자원을 얻기 위해 무엇을 사용해야 합니까?
A. 획득 기술
B. 협상 기술
C. 개인 및 팀 평가 ot
D. 요구 사항 분석 도구
Answer: A

NEW QUESTION: 4
Given:
public class Emp {
String fName;
String lName;
public Emp (String fn, String ln) {
fName = fn;
lName = ln;
}
public String getfName() { return fName; }
public String getlName() { return lName; }
}
and the code fragment:
List<Emp> emp = Arrays.asList (
new Emp ("John", "Smith"),
new Emp ("Peter", "Sam"),
new Emp ("Thomas", "Wale"));
emp.stream()
//line n1
.collect(Collectors.toList());
Which code fragment, when inserted at line n1, sorts the employees list in descending order of fName and then ascending order of lName?
A. .map(Emp::getfName).sorted(Comparator.reserveOrder().map(Emp::getlName).reserved
B. .sorted (Comparator.comparing(Emp::getfName).thenComparing(Emp::getlName))
C. .sorted
(Comparator.comparing(Emp::getfName).reserved().thenComparing(Emp::getlName))
D. .map(Emp::getfName).sorted(Comparator.reserveOrder())
Answer: C