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NEW QUESTION: 1
An engineer is configuring a second Cisco FMC as a standby device but is unable to register with the active unit. What is causing this issue?
A. The primary FMC currently has devices connected to it.
B. The licensing purchased does not include high availability
C. The code versions running on the Cisco FMC devices are different
D. There is only 10 Mbps of bandwidth between the two devices.
Answer: C
Explanation:
Explanation
https://www.cisco.com/c/en/us/td/docs/security/firepower/620/configuration/guide/fpmc-config-guide-v62/firepo

NEW QUESTION: 2
Examine the structure of the EMPLOYEES table.
NameNull?Type
---------------------- ------------
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
EMAILNOT NULLVARCHAR2(25)
PHONE NUMBERVARCHAR2(20)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(8,2)
COMMISSION_PCTNUMBER(2,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
A. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
B. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
C. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN
employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
D. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
Answer: B

NEW QUESTION: 3
Identify the two true statement about Action Scripts.
A. Action Scripts may run for new versions only.
B. You may define property definitions and property categories with