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NEW QUESTION: 1
Which switch feature prevents traffic on a LAN from being overwhelmed by continuous multicast or broadcast traffic?
A. VLAN trunking
B. storm control
C. port security
D. VTP pruning
Answer: B
Explanation:
Explanation/Reference:
Explanation:
A traffic storm occurs when packets flood the LAN, which creates excessive traffic and degrades network performance. The traffic storm control feature prevents LAN ports from being disrupted by a broadcast, multicast, or unicast traffic storm on physical interfaces from either mistakes in network configurations or from users issuing a DoS attack.
Reference: https://www.cisco.com/c/en/us/td/docs/switches/lan/catalyst6500/ios/12-2SX/configuration/ guide/book/storm.pdf

NEW QUESTION: 2
To import a target item list, the target list file you want to import __________.
A. Must be a file with a .tmp file extension
B. Must be a file with a .tcx file extension
C. Must be a file with a .tct file extension
D. Must be a file with a .txt file extension
Answer: B

NEW QUESTION: 3
Consider an OSPFv3 network with four parallel links between each pair of routers. Which measure can you use to reduce the CPU load and at the same time keep all links available for ECMP?
A. Configure ipv6 ospf database-filter all out on some interfaces.
B. Configure ipv6 ospf priority 0 on some interfaces.
C. Configure some interfaces as passive interface.
D. Configure some routers with a distribute list in ingress of the OSPFv3 process.
Answer: A
Explanation:
To filter outgoing link-state advertisements (LSAs) to an Open Shortest Path First version 3 (OSPFv3) interface, use the ipv6 ospf database-filter all out command in interface configuration mode. This can be done on some of the links to reduce the CPU load while still ensuring that all links in the equal cost path are still being used.

NEW QUESTION: 4
Refer to the exhibit.

At the end of an RSTP election process, which access layer switch port will assume the discarding role?
A. Switch3, port fa0/12
B. Switch4, port fa0/11
C. Switch3, port Gi0/1
D. Switch4, port fa0/2
E. Switch3, port Gi0/2
F. Switch3, port fa0/1
Answer: B
Explanation:
In this question, we only care about the Access Layer switches (Switch3 & 4). Switch 3 has a lower bridge ID than
Switch 4 (because the MAC of Switch3 is smaller than that of Switch4) so both ports of Switch3 will be in forwarding
state. The alternative port will surely belong to Switch4.
Switch4 will need to block one of its ports to avoid a bridging loop between the two switches. But how does Switch4
select its blocked port? Well, the answer is based on the BPDUs it receives from Switch3. A BPDU is superior than
another if it has:
1. A lower Root Bridge ID
2. A lower path cost to the Root
3. A lower Sending Bridge ID
4. A lower Sending Port ID
These four parameters are examined in order. In this specific case, all the BPDUs sent by Switch3 have the same Root
Bridge ID, the same path cost to the Root and the same Sending Bridge ID. The only parameter left to select the best
one is the Sending Port ID (Port ID = port priority + port index). In this case the port priorities are equal because they
use the default value, so Switch4 will compare port index values, which are unique to each port on the switch, and
because Fa0/12 is inferior to Fa0/1, Switch4 will select the port connected with Fa0/1 (of Switch3) as its root port and
block the other port -> Port fa0/11 of Switch4 will be blocked (discarding role)