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NEW QUESTION: 1
Given the following incorrect program:
class MyTask extends RecursiveTask<Integer> {
final int low;
final int high;
static final int THRESHOLD = /* . . . */
MyTask (int low, int high) { this.low = low; this.high = high; }
Integer computeDirectly()/* . . . */
protected void compute() {
if (high - low <= THRESHOLD)
return computeDirectly();
int mid = (low + high) / 2;
invokeAll(new MyTask(low, mid), new MyTask(mid, high));
Which two changes make the program work correctly?
A. The computeDirectly () method must be enhanced to fork () newly created tasks.
B. The MyTask class must be modified to extend RecursiveAction instead of RecursiveTask.
C. The THRESHOLD value must be increased so that the overhead of task creation does not dominate the cost of computation.
D. The compute () method must be changed to return an Integer result.
E. The midpoint computation must be altered so that it splits the workload in an optimal manner.
F. Results must be retrieved from the newly created MyTask Instances and combined.
Answer: D,F
Explanation:
D: the compute() method must return a result.
A: These results must be combined (in the lineinvokeAll(new MyTask(low, mid), new MyTask(mid, high));)
Note 1:A RecursiveTask is a recursive result-bearing ForkJoinTask.
Note 2: The invokeAll(ForkJoinTask<?>... tasks) forks the given tasks, returning when isDone holds for each task or an (unchecked) exception is encountered, in which case the exception is rethrown.
Note 3: Using the fork/join framework is simple. The first step is to write some code that performs a segment of the work. Your code should look similar to this:
if (my portion of the work is small enough) do the work directly else split my work into two pieces invoke the two pieces and wait for the results Wrap this code as a ForkJoinTask subclass, typically as one of its more specialized types RecursiveTask(which can return a result) or RecursiveAction.

NEW QUESTION: 2
Which type of port is used to connect and communicate with a SAN storage device on a Cisco MDS switch?
A. Ethernet
B. Fibre Channel
C. QSFP
D. serial
Answer: B

NEW QUESTION: 3
User jack makes use of the bash shell; his home directory is/export/home/jack.
What is the correct setting of umask, and where should it be set, to allow jack to create a shell script using the vi editor, that is executable by default?
A. umask value of 0002 set in /export/home/jack/.bashrc
B. umask value of 0722 set in /etc/profile
C. umask value of 0002 set in /etc/profile
D. It is not possible to make a script executable without using the chmod command.
E. umask value of 0722set In /export/home/jack/.bashrc
Answer: C
Explanation:
The user file-creation mode mask (umask) is use to determine the file permission for newly created files. It can be used to control the default file permission for new files. It is a four-digit octal number. You can setup umask in /etc/bashrc or /etc/profile file for all users. By default most Unix distro set
it to 0022 (022) or 0002 (002). In short,

NEW QUESTION: 4
An enter pose customer will deploy a centralized unified communications application to provide voice, video, and instant messaging to their branch offices Some of the branch offices are located m remote locations and are connected via a 1 5 Mb's Layer 3 VPN connection Which two actions are the most cost-effective ways to ensure that this new application is implemented properly? (Choose two)
A. Set LFI on the WAN connections to interleave the small voice packets with the large data packets
B. Use a low bitrate codec such as G.711
C. Set WAN optimization on the CE router to compress the voice packets for improved bandwidth utilization and performance
D. Set voice activity detection to avoid sending packets when the conversation is silent
E. Enable VRF-Lite on the CE router to create a separate voice VRF
F. Use a low bitrate codec such as G 729
Answer: D,F