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NEW QUESTION: 1
A newborn infant is exhibiting signs of respiratory distress. Which of the following would the nurse recognize as the earliest clinical sign of respiratory distress?
A. Increased respirations
B. Sternal and subcostal retractions
C. Cyanosis
D. Decreased respirations
Answer: B
Explanation:
Explanation
(A) Cyanosis is a late clinical sign of respiratory distress. (B) Rapid respirations are normal in a newborn. (C) The newborn has to exert an extra effort for ventilation, which is accomplished by using the accessory muscles of ventilation. The diaphragm and abdominal muscles are immature and weak in the newborn. (D) Decreased respirations are a late clinical sign. In the newborn, decreased respirations precede respiratory failure.

NEW QUESTION: 2
HOTSPOT





Answer:
Explanation:

NEW QUESTION: 3
You use Microsoft Visual Studio 2010 and Microsoft .NET Framework 4 to create an application.
The application contains the following code segment. (Line numbers are included for reference only.)
01 class DataAccessLayer
02 {
03 private static string connString;
04
05 ...
06 public static DataTable GetDataTable(string command){
07
08 ...
09 }
10 }
You need to define the connection life cycle of the DataAccessLayer class. You also need to ensure that
the application uses the minimum number of connections to the database.
What should you do?
A. Replace line 01 with the following code segment.
class DataAccessLayer : IDisposable
Insert the following code segment to line 04.
private SqlConnection conn = new SqlConnection(connString);
public void Open(){
conn.Open();
}
public void Dispose(){
conn.Close();
}
B. Insert the following code segment at line 07. using (SqlConnection conn = new SqlConnection(connString)){
conn.Open();
}
C. Insert the following code segment at line 04. private static SqlConnection conn = new SqlConnection(connString); public static void Open(){
conn.Open();
}
public static void Close(){
conn.Close();
}
D. Insert the following code segment at line 04. private SqlConnection conn = new SqlConnection(connString); public void Open(){
conn.Open();
}
public void Close(){
conn.Close();
}
Answer: B