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NEW QUESTION: 1
When an activity cannot be estimated with a reasonable degree of confidence, the work within the activity is decomposed into more detail using which type of estimating?
A. Analogous
B. Parametric
C. Three-point
D. Bottom-up
Answer: D
Explanation:
Explanation/Reference:
Explanation:
7.2.2.4 Bottom-Up Estimating
Bottom-up estimating is a method of estimating a component of work. The cost of individual work packages or activities is estimated to the greatest level of specified detail. The detailed cost is then summarized or
"rolled up" to higher levels for subsequent reporting and tracking purposes. The cost and accuracy of bottom-up cost estimating are typically influenced by the size and complexity of the individual activity or work package.

NEW QUESTION: 2
Examine the following partial outputs from two routing debug commands; then answer the question below.
# get router info kernel
tab=254 vf=0 scope=0type=1 proto=11 prio=0 0.0.0.0/0.0.0.0/0- 0.0.0.0/0 pref=0.0.0.0 gwy=10.200.1.254 dev=2(port1) tab=254 vf=0 scope=0type=1 proto=11 prio=10 0.0.0.0/0.0.0.0/0- 0.0.0.0/0 pref=0.0.0.0 gwy=10.200.2.254 dev=3(port2) tab=254 vf=0 scope=253type=1 proto=2 prio=0 0.0.0.0/0.0.0.0/.- 10.0.1.0/24 pref=10.0.1.254 gwy=0.0.0.0 dev=4(port3)
# get router info routing-table all s*0.0.0.0/0 [10/0] via 10.200.1.254, portl [10/0] via 10.200.2.254, port2,
[10/0] dO.0.1.0/24 is directly connected, port3 dO.200.1.0/24 is directly connected, portl d0.200.2.0/24 is directly connected, port2 Which outbound interface or interfaces will be used by this FortiGate to route web traffic from internal users to the Internet?
A. port3.
B. port2.
C. port!
D. Both portl and port2.
Answer: B

NEW QUESTION: 3
You have a database named DB1 that uses simple recovery mode.
Full backups of DB1 are taken daily and DB1 is checked for corruption before each backup.
There was no corruption when the last backup was complete.
You run the sys.columns catalog view and discover corrupt pages.
You need to recover the database. The solution must minimize data loss.
What should you do?
A. Run DBCC CHECKDB and specify the REPAIT_REBUILD parameter.
B. Run RESTORE DATABASE WITH PAGE.
C. Run DBCC CHECKDB and specify the REPAIR_ALLOW_DATA_LOSS parameter.
D. Run RESTORE DATABASE WITH RECOVERY.
Answer: B
Explanation:
A page restore is intended for repairing isolated damaged pages. Restoring and recovering a few individual pages might be faster than a file restore, reducing the amount of data that is offline during a restore operation.
RESTORE DATABASE WITH PAGE
Restores individual pages. Page restore is available only under the full and bulk-logged recovery models.
References: https://docs.microsoft.com/en-us/sql/t-sql/statements/restore-statements- transact-sql

NEW QUESTION: 4



A. Option C
B. Option B
C. Option A
D. Option D
Answer: B
Explanation:
Explanation
Horizontal partitioning divides a table into multiple tables. Each table then contains the same number of columns, but fewer rows. For example, a table that contains 1 billion rows could be partitioned horizontally into 12 tables, with each smaller table representing one month of data for a specific year. Any queries requiring data for a specific month only reference the appropriate table.
NEWSEQUENTIALID creates a GUID that is greater than any GUID previously generated by this function on a specified computer since Windows was started. After restarting Windows, the GUID can start again from a lower range, but is still globally unique. When a GUID column is used as a row identifier, using NEWSEQUENTIALID can be faster than using the NEWID function. This is because the NEWID function causes random activity and uses fewer cached data pages. Using NEWSEQUENTIALID also helps to completely fill the data and index pages.
References:https://msdn.microsoft.com/en-us/library/ms189786.aspx