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NEW QUESTION: 1
DRAG DROP
You administer an Azure Virtual Machine (VM) named server1. The VM is in a cloud service named ContosoService1.
You discover that the VM is experiencing storage issues due to increased application logging on the server.
You need to create a new 256-GB disk and attach it to the server.
Which Power Shell cmdlets should you use? To answer, drag the appropriate cmdlet to the correct location in the Power Shell command. Each cmdlet may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.

Answer:
Explanation:

Explanation:

This example gets a virtual machine object for the virtual machine named "MyVM" in the
"myservice" cloud service, updates the virtual machine object by attaching an existing data disk from the repository using the disk name, and then updates the Azure virtual machine.
Windows PowerShell
C:\PS>Get-AzureVM "myservice" -Name "MyVM" `| Add-AzureDataDisk -Import -DiskName "MyExistingDisk" -LUN 0 `| Update-AzureVM
References:
http://msdn.microsoft.com/en-us/library/dn495298.aspx

NEW QUESTION: 2
Which Cisco ISE persona must run on dedicated hardware?
A. Inline Posture
B. Policy Services
C. Monitoring
D. Distributed Policy
E. Centralized
F. Administrative
G. Standalone
Answer: A
Explanation:
Section: (none)
Explanation/Reference:
Explanation:

NEW QUESTION: 3
There are three servers in the pool: 172.16.20.1, 172.16.20.2, and 172.16.20.3, with the virtual IP address
10.0.20.88.
A user CANNOT connect to an HTTP application. To understand the problem and find a solution, the LTM Specialist runs two concurrent traces on the LTM device, with the following results:
Trace on client side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on 0.0, link-type EN10MB (Ethernet), capture size 96 bytes
22:22:07.423759 IP 172.16.20.100.53875 > 10.0.20.88.80: S 998346084:998346084(0) win 5840 <mss
1460,sackOK,timestamp 67942058 0,nop,wscale 4>
22:22:07.424056 IP 10.0.20.88.80 > 172.16.20.100.53875: S 4671780:4671780(0) ack 998346085 win 4380
<mss 1460,nop,wscale 0,nop,nop,timestamp 2392362490 67942058,sackOK,eol>
22:22:07.424776 IP 172.16.20.100.53875 > 10.0.20.88.80: . ack 1 win 365 <nop,nop,timestamp 67942058
2392362490>
22:22:07.424790 IP 172.16.20.100.53875 > 10.0.20.88.80: P 1:149(148) ack 1 win 365 <nop,nop,timestamp
67942058 2392362490>
22:22:07.424891 IP 10.0.20.88.80 > 172.16.20.100.53875: . ack 149 win 4528 <nop,nop,timestamp
2392362491 67942058>
22:22:12.024850 IP 10.0.20.88.80 > 172.16.20.100.53875: R 1:1(0) ack 149 win 4528
6 packets captured
6 packets received by filter
0 packets dropped by kernel
Trace on server side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on internal, link-type EN10MB (Ethernet), capture size 96 bytes
22:22:07.424881 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392362491 0,sackOK,eol>
22:22:08.424893 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392363491 0,sackOK,eol>
22:22:09.625082 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,nop,wscale 0,nop,nop,timestamp 2392364691 0,sackOK,eol>
22:22:10.825194 IP 172.16.20.100.53875 > 172.16.20.2.80: S 51116678:51116678(0) win 4380 <mss
1460,sackOK,eol>
4 packets captured
4 packets received by filter
0 packets dropped by kernel
What should the LTM Specialist do to solve the problem?
A. Modify the monitor of the pool.
B. Edit the packet filter rules.
C. Enable the virtual server.
D. Configure the virtual server to use SNAT.
Answer: D

NEW QUESTION: 4
Your database contains tables named Products and ProductsPriceLog. The Products table contains columns named ProductCode and Price. The ProductsPriceLog table contains columns named ProductCode, OldPrice, and NewPrice.
The ProductsPriceLog table stores the previous price in the OldPrice column and the new price in the NewPrice column.
You need to increase the values in the Price column of all products in the Products table by 5 percent. You also need to log the changes to the ProductsPriceLog table.
Which Transact-SQL query should you use?
A. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, deleted.Price, inserted.Price
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
B. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, inserted.Price, deleted.Price
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
C. UPDATE Products SET Price = Price * 1.05
INSERT INTO ProductsPriceLog (ProductCode, CldPnce, NewPrice;
SELECT ProductCode, Price, Price * 1.05 FROM Products
D. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, deleted.Price, inserted.Price *
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
Answer: A
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms177564.aspx