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NEW QUESTION: 1
Which technique is deployed to harden network devices?
A. port-by-port router ACLs
B. VLAN ACLs
C. infrastructure ACLs
D. transmit ACLs
Answer: C

NEW QUESTION: 2
GEM : SETTING ::
A. portrait : subject
B. ring : necklace
C. painting : milieu
D. diamond : gold
E. building : scaffold
Answer: E
Explanation:
Explanation/Reference:
Explanation:
This is a "place for" analogy. A GEM is placed within a SETTING (framework) in jewelry, just as a building is constructed within the framework of a scaffold.

NEW QUESTION: 3
You have an Azure web app named WebApp1.
You need to provide developers with a copy of WebApp1 that they can modify without affecting the production WebApp1. When the developers finish testing their changes, you must be able to switch the current line version of WebApp1 to the new version.
Which command should you run prepare the environment? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Box 1: New-AzureRmWebAppSlot
The New-AzureRmWebAppSlot cmdlet creates an Azure Web App Slot in a given a resource group that uses the specified App Service plan and data center.
Box 2: -SourceWebApp
References:
https://docs.microsoft.com/en-us/powershell/module/azurerm.websites/new-azurermwebappslot

NEW QUESTION: 4
Exhibit

Examine the data in the EMPLOYEES and DEPARTMENTS tables.
You want to retrieve all employees' last names, along with their manager's last names and their department names. Which query would you use?
A. SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGT OUTER JOIN departments d ON (e.department_id = d.department_id);
B. SELECT last_name, manager_id, department_name
FROM employees e
JOIN departments d ON (e.department_id = d.department_id) ;
C. SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)
D. SELECT last_name, manager_id, department_name
FROM employees e
FULL OUTER JOIN departments d ON (e.department_id = d.department_id);
E. SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
F. SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
Answer: F