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NEW QUESTION: 1
You administer two servers AO-AG2 and ao-ag2. Microsoft SQL Server 2016 Enterprise Edition is running on both servers.
You need to configure a new Microsoft SQL Server Always On Availability Group.
Which three actions should you perform? To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.

Answer:
Explanation:

Explanation

Step 1: Create a Windows Server Failover Clustering (WSFC) cluster with AO-AG1 and AO-AG2 as nodes.
Since AlwaysOn Availability Groups require a Windows Server Failover Cluster, we first need to add the Windows Failover Cluster Feature to all the machines running the SQL Server instances that we will configure as replicas.
Step 2: Configure a secondary replica
In the Specify Replicas page, under the Replicas tab, click the Add Replicas button and connect to the other SQL Server instances that you joined as nodes in your Windows Server Failover Cluster.
Step 3: Create an Always On Availability Group and select the availability databases Once the Windows Server Failover Cluster has been created, we can now proceed with enabling the AlwaysOn Availability Groups feature in SQL Server 2012. This needs to be done on all of the SQL Server instances that you will configure as replicas in your Availability Group.

NEW QUESTION: 2
Which of the following aggregation options must you define as an exception aggregation?
Choose the correct answers.
A. Last Value
B. Maximum
C. Counter
D. Average
E. Summation
F. Minimum
Answer: A,C,D

NEW QUESTION: 3
You begin to register a component using the Registration Wizard. What should you do based on the values that appear in the dialog box?

A. Change the user-facing fields to mixed case and make them less technical, and then continue registering the component.
B. Select the Always use default local node? check box and then continue the registration.
C. Stop the registration process to investigate why this component is already registered.
D. Continue registering the component as is.
Answer: C