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NEW QUESTION: 1
In cloud computing, the network can be divided into two parts: virtual network and physical network.
A. wrong
B. Yes
Answer: B

NEW QUESTION: 2

組織は最近、買収を通じて成長しました。購入した2つの会社が同じIP CIDR範囲を使用しています。 AnyCompany A（VPC-A）がAnyCompany B（VPC-B）のIPアドレス10.0.0.77を持つサーバーと通信できるようにするための新しい短期要件があります。 AnyCompany Aは、AnyCompany C（VPC-C）のすべてのリソースとも通信する必要があります。ネットワークチームはVPCピアリンクを作成しましたが、VPC-AとVPC-B間の通信に問題があります。調査後、チームはVPCのルーティングテーブルが正しくないと考えています。
AnyCompany Bのデータベースに加えて、AnyCompany AがAnyCompany Cと通信できるようにする構成は何ですか？
A. VPC-Aでは、pcx-ABおよびpcx-ACで動的ルート伝播を有効にします.VPC-Bでは、動的ルート伝播を有効にし、セキュリティグループを使用して、VPCピアpcxでIPアドレス10.0.0.77/32のみを許可します-AB。VPC-Cで、ピアpcx-ACのVPC-Aを使用した動的ルート伝播を有効にします。
B. VPC-Aで、VPCピアpcx-AB全体でVPC-B CIDR範囲（10.0.0.0/24）の静的ルートを作成します。VPCピアpcx-AC全体で10.0.0.0/16の静的ルートを作成します。 VPC-Bで、ピアpcx-ABにVPC-A CIDR（172.16.0.0/24）の静的ルートを作成します。VPC-Cで、VPC-A CIDR（172.16.0.0/24）の静的ルートを作成します。ピアpcx-AC。
C. VPC-Aで、VPCピアpcx-AB全体でVPC-B CIDR（10.0.0.77/32）データベースの静的ルートを作成します。VPCピアpcx-ACでVPC-C CIDRの静的ルートを作成します。 VPC-Bで、ピアpcx-ABにVPC-A CIDR（172.16.0.0/24）の静的ルートを作成します。VPC-Cで、VPC-A CIDR（172.16.0.0/24）の静的ルートを作成します。ピアpcx-AC。
D. VPC-Aで、VPCピアpcx-ACのIPアドレス10.0.0.77/32をブロックするネットワークアクセスコントロールリストを作成します。VPC-Aで、VPC-B CIDR（10.0.0.0/ 24）pcx-ABおよびpcx-AC上のVPC-C CIDR（10.0.0.0/24）の静的ルートVPC-Bで、ピア全体にVPC-A CIDR（172.16.0.0/24）の静的ルートを作成しますpcx-AB。VPC-Cで、ピアpcx-AC全体にVPC-A CIDR（172.16.0.0/24）の静的ルートを作成します。
Answer: C

NEW QUESTION: 3
Given the code fragment:

And given the requirements:
1. Process all the elements of the array in the order of entry.
2. Process all the elements of the array in the reverse order of entry.
3. Process alternating elements of the array in the order of entry.
Which two statements are true? (Choose two.)
A. Requirements 1, 2, and 3 can be implemented by using the standard for loop.
B. Requirement 1 can be implemented by using the enhanced for loop.
C. Requirements 2 and 3 CANNOT be implemented by using the standard for loop.
D. Requirements 1, 2, and 3 can be implemented by using the enhanced for loop.
E. Requirement 3 CANNOT be implemented by using either the enhanced for loop or the standard for loop.
Answer: B,E