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NEW QUESTION: 1
What does the union operation perform when attempting to execute an SQL Injection through a web form?
A. Union operation is used to combine two tables
B. Union operation permits combining two results
C. Union operation is used to combine two accounts
D. Union operation permits changing the DB password
Answer: B

NEW QUESTION: 2
Which Activity Duration Estimating technique incorporates additional timing for contingency purposes?
A. Expert Judgment
B. Optimistic Estimates
C. Analogous Estimating
D. Reserve Analysis
Answer: D
Explanation:
Explanation/Reference:
Explanation:
6.5.2.6 Reserve Analysis
Duration estimates may include contingency reserves, sometimes referred to as time reserves or buffers, into the project schedule to account for schedule uncertainty. Contingency reserves are the estimated duration within the schedule baseline, which is allocated for identified risks that are accepted and for which contingent or mitigation responses are developed. Contingency reserves are associated with the "known- unknowns," which may be estimated to account for this unknown amount of rework.
As more precise information about the project becomes available, the contingency reserve may be used, reduced, or eliminated. Contingency should be clearly identified in schedule documentation.
[..]
Estimates may also be produced for the amount of management reserve of time for the project.
Management reserves are a specified amount of the project duration withheld for management control purposes and are reserved for unforeseen work that is within scope of the project. Management reserves are intended to address the "unknown-unknowns" that can affect a project. Management reserve is not included in the schedule baseline, but it is part of the overall project duration requirements. Depending on contract terms, use of management reserves may require a change to the schedule baseline.

NEW QUESTION: 3
Given:

What is the result?
A. p001 Widget
p002 Large Widget
B. compilation fails
C. p001 Widget
p002 X-Large Widget
D. p002 Large Widget
p001 Widget
E. p002 X-large Widget
p001 Widget
Answer: C
Explanation:
Explanation/Reference:
Explanation: Compiles fine. Output is:
P001 Widget
P002 X-Large Widget
Line: partList.put("P002", "X-Large Widget"); >> overwrites >> line:partList.put("P002", "Large Widget");
put
V put(K key, V value)
Associates the specified value with the specified key in this map (optional operation). If the map previously
contained a mapping for the key, the old value is replaced by the specified value. (A map m is said to
contain a mapping for a key k if and only if m.containsKey(k) would return true.)
Parameters:
key - key with which the specified value is to be associated
value - value to be associated with the specified key
Returns the previous value associated with key, or null if there was no mapping for key. (A null return can
also indicate that the map previously associated null with key, if the implementation supports null values.)