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NEW QUESTION: 1
솔루션 아키텍트는로드 밸런서 뒤에서 Amazon EC2 인스턴스에서 실행되는 웹 애플리케이션을 설계하고 있습니다. 전송중인 모든 데이터는 암호화되어야 합니다.
어떤 솔루션이 암호화 요구 사항을 충족합니까? (2 개 선택)
A. HTTPS 리스너와 함께 NLB (Network Load Balancer)를 사용한 다음 NLB 및 EC2 인스턴스에 SSL 인증서를 설치하십시오.
B. 통과 모드에서 ALB (Application Load Balancer)를 사용한 다음 EC2 인스턴스에서 SSL을 종료하십시오.
C. TCP 리스너와 함께 ALB (Application Load Balancer)를 사용한 다음 EC2 인스턴스에서 SSL을 종료하십시오.
D. HTTPS 리스너와 함께 ALB (Application Load Balancer)를 사용한 다음 ALB 및 EC2 인스턴스에 SSL 인증서를 설치하십시오.
E. TCP 리스너와 함께 NLB (Network Load Balancer)를 사용한 다음 EC2 인스턴스에서 SSL을 종료하십시오.
Answer: D,E

NEW QUESTION: 2
Marketplace conditions are an input to which one of the following processes?
A. Close procurements
B. Plan procurement management
C. Conduct procurements
D. Control procurements
Answer: B
Explanation:
Enterprise environmental factors, which include marketplace conditions that the team needs to be aware of as it develops its plans for purchases and acquisition, are an input to the plan procurement management process. [Planning] PMI@, PMBOK@ Guide, 2013, 362

NEW QUESTION: 3
상관은 회귀 분석과 함께 자주 사용되는 용어이며 상관 계수 r의 값으로 측정됩니다. r 값에 대한 가장 좋은 설명은 다음과 같습니다.
A. 두 변수 사이의 상대적인 관계의 척도입니다.
B. 음의 무한대에서 양의 무한대까지의 크기 범위.
C. 독립 변수로 분산을 해석합니다.
D. 항상 긍정적입니다.
Answer: A
Explanation:
The coefficient of correlation r) measures the strength of the linear relationship between the dependent and independent variables. The magnitude of r is independent of the scales of measurement of x and y. The coefficient lies between -1.0 and +1.0. A value of zero indicates no linear relationship between the x and y variables. A value of +1.0 indicates a perfectly direct relationship, and a value of-1.0 indicates a perfectly inverse relationship.

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <map>
using namespace std;
int main() {
int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"}; multimap<int, string> m; for (int i = 0; i < 10; i++) { m.insert(pair<int, string>(t[i], s[i]));
}
if (m.count(3) == 2) {
m.erase(3);
}
for (multimap<int, string>::iterator i = m.begin(); i != m.end(); i++) { cout << i?>first << " ";
}
return 0;
}
A. program outputs: 1 1 2 2 4 4 5 5
B. program outputs: 1 1 2 2 3 4 4 5 5
C. program outputs: 1 2 4 5
D. program outputs: one two three four five
E. program outputs: 1 2 3 4 5
Answer: A