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NEW QUESTION: 1
AWS Direct Connectを使用してAmazon Virtual Private Cloud（Amazon VPC）に接続する前に、次のどれに従う必要がありますか？
A. インターネット上のネットワークを識別するために、公共の自律システム番号（ASN）を提供します。
B. 仮想プライベートゲートウェイを作成し、仮想プライベートクラウド（VPC）に接続します。
C. プライベートIPアドレスを122.x.x.xの範囲でネットワークに割り当てます。
D. 各ボーダーゲートウェイプロトコル（BGP）セッションのパブリックIPアドレスを提供します。
Answer: B
Explanation:
AWS Direct Connectを使用してAmazon Virtual Private Cloud（Amazon VPC）に接続するには、最初に以下を実行する必要があります。
インターネット上のネットワークを識別するために、プライベート自律システム番号（ASN）を提供します。
Amazonは、169.x.x.xの範囲のプライベートIPアドレスを割り当てます。仮想プライベートゲートウェイを作成し、VPCに接続します。
http://docs.aws.amazon.com/directconnect/latest/UserGuide/Welcome.html

NEW QUESTION: 2
Auf einem DNS-Server, auf dem Windows Server 2016 ausgeführt wird, möchten Sie zwei neue primäre Zonen mit den Namen adatum.com und contoso.com erstellen. Sie haben folgende Anforderungen an die Zonen:
* Stellen Sie sicher, dass Computer in Ihrem Netzwerk Datensätze automatisch in der Zone adatum.com registrieren können.
* Stellen Sie sicher, dass Datensätze, die zwei Wochen veraltet sind, automatisch aus der contoso.com-Zone gelöscht werden.
Was müssen Sie für jede Zone konfigurieren? Wählen Sie zum Beantworten die entsprechenden Optionen im Antwortbereich aus.

Answer:
Explanation:

NEW QUESTION: 3
Dynamics 365 for Finance and Operationsシステム管理者です。
いくつかの新しいユースケースシナリオをサポートするようにシステムを構成する必要があります。
どの機能を使用する必要がありますか？回答するには、回答エリアで適切なオプションを選択します。
注：それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

Explanation


References:
https://docs.microsoft.com/en-us/dynamics365/unified-operations/dev-itpro/user-interface/task-recorder?toc=/fin

NEW QUESTION: 4
Given classes defined in two different files:
1.package util;
2.public class BitUtils {
3.public static void process(byte[]) { /* more code here */ }
4.}
1.package app;
2.public class SomeApp {
3.public static void main(String[] args) {
4.byte[] bytes = new byte[256];
5.// insert code here
6.}
7.}
What is required at line 5 in class SomeApp to use the process method of BitUtils?
A. import util.BitUtils.*; process(bytes);
B. util.BitUtils.process(bytes);
C. process(bytes);
D. SomeApp cannot use methods in BitUtils.
E. BitUtils.process(bytes);
Answer: B